4[2(x-2)-(x+4)]=0

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Solution for 4[2(x-2)-(x+4)]=0 equation:


Simplifying
4[2(x + -2) + -1(x + 4)] = 0

Reorder the terms:
4[2(-2 + x) + -1(x + 4)] = 0
4[(-2 * 2 + x * 2) + -1(x + 4)] = 0
4[(-4 + 2x) + -1(x + 4)] = 0

Reorder the terms:
4[-4 + 2x + -1(4 + x)] = 0
4[-4 + 2x + (4 * -1 + x * -1)] = 0
4[-4 + 2x + (-4 + -1x)] = 0

Reorder the terms:
4[-4 + -4 + 2x + -1x] = 0

Combine like terms: -4 + -4 = -8
4[-8 + 2x + -1x] = 0

Combine like terms: 2x + -1x = 1x
4[-8 + 1x] = 0
[-8 * 4 + 1x * 4] = 0
[-32 + 4x] = 0

Solving
-32 + 4x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '32' to each side of the equation.
-32 + 32 + 4x = 0 + 32

Combine like terms: -32 + 32 = 0
0 + 4x = 0 + 32
4x = 0 + 32

Combine like terms: 0 + 32 = 32
4x = 32

Divide each side by '4'.
x = 8

Simplifying
x = 8

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